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Analyze Test Confidence to Enhance Throughput

Christopher Jones, M/A-COM Division of AMP, Lowell, MA -- Test & Measurement World, 9/1/1999

At M/A-COM’s Semiconductor Business Unit, we test more than 4 million RF ICs per week. A major factor in reaching this capacity has been our attention to improving test yield. We have observed that poor device-lead to test-board contact is a major cause of low yield and is a common issue for RF devices and plunge-to-board testing.

To increase our yield, we needed to improve our “test confidence”—the probability of making a good connection. We determine test confidence by measuring and monitoring connection repeatability, and we use it to qualify new automated part handlers and test interfaces.

The test-confidence measurement is based on the relationship between the yields of a prime test and a retest of devices that failed the prime test. Devices that pass the retest do so because their performance is borderline or because of poor connection repeatability. You can eliminate borderline devices from the retest yield by setting specification limits that account for tester variation.The retest yield will then depend on connection repeatability alone.

Your test confidence will determine the value of retest. Consider the following example: Assume 100 parts that have an absolute yield of 90% are entered into a test in which your test confidence is 80%. The first-pass test results will equal the product of parts, absolute yield, and confidence, or

100 x 0.90 x 0.80 = 72 parts

Of the 28 parts that failed, you know only 10 are bad (90% absolute yield); therefore, you know that 18 good parts failed the test because of poor contact repeatability. The retest will pass 80% of the 18 good parts, or 14 parts.

Overall, you passed 86 parts out of a possible 90, and you performed 128 tests to measure 100 parts. From an operations point of view, you rejected four good parts and increased test time by 28%. This is the effect of low test confidence.

This example is expanded in Figure 1, which shows the effects of varying test confidence on the cumulative yield for a three-pass test—an initial test and two retests. Low test confidence clearly leads to yield loss and excessive retesting. Our experience suggests these rules of thumb:

  • Don’t run a test if confidence is lower than 85%.
  • Use two passes for confidence in the range of 85% to 95%.
  • A single test is only realistic for confidence above 95%.

     

    09t3fig1.gif (11027 bytes)
    Figure 1. Low test confidence degrades test yield, requiring costly and time-consuming retesting.

Deriving Test Confidence
You can calculate your test confidence with a series of equations. Assume a sample of devices, S1, are submitted to test and that there are S1G good devices within the group. The probability that any device in the sample is good, P(S1G), is equal to the absolute yield, Y, or the ratio of good devices to total devices:

wpe9.jpg (1506 bytes)

As discussed in the previous example, the probability that a device passes the first test, P(T1P), is not equal to the absolute yield. The first-pass yield, Y1, equals the probability that a device is good times the test confidence, C,

wpeA.jpg (1554 bytes)

and the number of devices to pass the first test, T1P, is equal to the test quantity times the yield:

wpeB.jpg (1393 bytes)

As a result, the first-pass yield equals the absolute yield scaled down by the test confidence. Inverting this relationship, you can solve for the absolute yield:

wpeC.jpg (1032 bytes)

Thus, given a known confidence rating you can forecast the absolute yield at the end of the first-pass test and determine if the value of the second-pass test is worth the effort of performing it.

You can continue to solve for test confidence by looking at the second-pass test. Test 2 sample size, S2, is equal to the original quantity less the devices that passed the first test:

wpeD.jpg (1150 bytes)

The probability that a device is good, P(S2G), is equal to the ratio of good devices to total devices:

wpeE.jpg (1891 bytes)


The probability that a device passes the second test, P(T2P) or Y2, equals the probability that a device is good times the probability that a good connection is made:

wpeF.jpg (1633 bytes)

Given these equations, you can solve for test confidence in measurable terms. Begin with the last equation in terms of test confidence:

wpe10.jpg (1337 bytes)

and substitute for P(S2G) and then T1P:

wpe11.jpg (2878 bytes)

Factor S1 and substitute for Y:

wpe12.jpg (2758 bytes)

Then solve for test confidence:

wpe13.jpg (1477 bytes)

Simplifying the Analysis
The equations presented here are straightforward to calculate, but may not be effective to put on to a manufacturing floor where rapid pace and a variety of skill levels exist. Figure 2 shows a graphical representation of confidence and absolute yield plotted as functions of first- and second-pass yield. Given this plot, you can easily estimate any two variables given that two are known. T&MW

09t3fig2.gif (23361 bytes)
Figure 2. The equations presented in this article are straightforward but might not be appropriate to solve on the production floor. This worksheet presents a graphical approach to determining test confidence and absolute yield given first- and second-pass test yields.

Christopher Jones is test engineering manager at AMP MA/COM’s Semiconductor Business Unit in Lowell, MA. He received his B.S.E.E. from the University of Massachusetts Amherst and an M.S. in Manufacturing Engineering from Boston University.

Copyright 1999, Test & Measurement World. Published by Cahners Business Information, Newton, MA.

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